If such a number has a second digit of

*m*, then its first digit is 2

*m*, its fourth digit is

*m* + 2, and its third digit is

*m* + 5.

The sum of the four digits is then *m* + 2*m* + (*m* + 5) + (*m* + 2) = 5*m* + 7. To be a multiple of 3, the digits must add to a multiple of 3, so 5*m* + 7 must be a multiple of 3. This happens when *m* is 1, 4, or 7, but when *m* is 7, *m* + 5 is not a digit. Thus, the two numbers are 2163 (when *m* = 1) and 8496(when *m* = 4). The difference of these two numbers is 8496 âˆ’ 2163 = 6333.

Hence, the sum of the digits of the difference is 6 + 3 + 3 + 3 = 15

Hence, option 2.