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TESTfunda
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22-Nov-2008, 02:25:50 AM
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TestFunda
Posts 1916
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Question Of The Day (22-November-08)
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22-Nov-2008, 02:25:50 AM
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implex
Posts 323
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as n is even we assume it to be 2k
so we have 4k^2 trees
and 4k+1 trees everyday
if m+1 be the total no of days and T be the number of tree on the last day then
4k^2= m(4k+1) +T
4k^2-T=(4k+1)m
4k+1 divided lhs
T=13 is possible for k=4 and m =3
similarly we can see all primes can be obtained
so only value left is 28
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22-Nov-2008, 07:30:54 AM
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celebratingLife
Posts 14
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Answer choice (3) 17
Now when n^2 is divided by 2n+1, when n is an even integer, the remainder is of the series 4,7,10,13...Only 17 can't be a part of this series.
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22-Nov-2008, 08:35:42 AM
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pratyush.mathur
Posts 35
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Last digit forms an AP
7,10,13,16,19,22.....
So ans is 17.
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22-Nov-2008, 09:31:07 AM
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cvsrs
Posts 7
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on any day the no.of trees has to be an odd no., irrespective of value of "n", 2n+1 is definitely a odd no. and the only even no in the answer set is 28. ODD MAN OUT!!!! ;-) so 28's the answer.
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22-Nov-2008, 10:03:47 AM
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surver
Posts 10
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the answer is option 4 for sure bcoz
the series is 5,9,13,17,21,25,29,31.........76 satifing that n is even.
therefore on the final day he will be able to calculate these odd values only.
now if we observe for 31 he has to first count 29 trees then 2 more trees.Now 2 is even whereas we are told it has to be odd only.
for all other values the no of trees he has to count are 3 e.g in case of say 79=(76(part of series)+3).
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22-Nov-2008, 11:00:07 AM
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Anshul_msit
Posts 14
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Its simple....the answer is 17(Option 3)...start putting the values of n=4,6,8,10......the last day trees to be studied would come out to be 7,10,13,16,19......,28.......,79...the only value that does not come is 17.....!!!!!!...
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22-Nov-2008, 11:41:07 AM
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snehaaga
Posts 883
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i thnk option 2...
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22-Nov-2008, 12:07:42 PM
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richa1
Posts 34
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it 28.....
as he counts 2n+1 trees everyday..and n is an even no... so 2n+1 is an odd no...
so it cannot b any even no..
so ans is 28.
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22-Nov-2008, 05:44:01 PM
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veneetkumarcv
Posts 1
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its 28, as it is clear that 28 is an even no: which doesn't suits to equation 2n+1, simple...
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22-Nov-2008, 06:50:13 PM
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balravneet
Posts 1
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answer is 17
the series is 7,10,13,.....
17 is not a term of this series
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22-Nov-2008, 07:10:13 PM
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maninder24
Posts 1
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as there are a total of n^2 trees and at rate of 2n+1 trees per day he would take a total of n/2 days with n^2-(n/2-1)(2n+1) days left for the last day that is (3/2)n +1 for the last day. out of the given option only 17 cannot come in the series where n=2,4,6,8....... hence it is 17
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22-Nov-2008, 07:21:06 PM
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deepika_goel
Posts 2
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the answer is 28
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22-Nov-2008, 08:27:44 PM
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mojahidkhan
Posts 33
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i think answer is 17
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22-Nov-2008, 10:21:56 PM
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Bodhajnya
Posts 2
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its 17...
coz.. n^2 is dvided by (2n+1) it gives a remainder startng from 4 ,7,10.... nd so on..
in this series 17 is not a number..
hence answer will b 17....
simple..
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23-Nov-2008, 01:51:53 AM
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karsh
Posts 1
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i agree with u. the ans has to be 28 coz (2n+1) is odd no. so on any day he is counting odd no. of trees. 28 being the even no. is the ans of the ques.
karsh.
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24-Nov-2008, 11:41:29 AM
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tswati
Posts 10
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option 2) 28
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