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Question of the Day (27-Nov-14)

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(1 + x + x2 )55 = a0 + a1x + a2x2 + a3x3 + … + a110x110 where the ais are the coefficients of powers of x.

What is the remainder when 2n × (a1 + a3 + a5 + a+… + a109) is divided by 4, where n is a natural number and n > 1? 

OPTIONS
 
 1)0
 2)
3
 3)1
 4)
Cannot be determined

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